DOI:
VOLUME 1 – APRIL ISSUE 2
*Paul T. E. Cusack, BScE, DULE
23 Park Ave. Saint John, NB E2J 1R2 Canada.
ABSTRACT
Vit B12=C63H88CoN14O14P
Vit C C6H8O6
Vit D3 C27H44O
now
[Vit B12-Fe]/Ca=Vit C/Vit D=1/√2 ⇒t=π/4
(B12-Fe) Vit D=Ca (Vit C)
[.1354-55.845]/ 40.078=176.12/384.6436
sin 45°=cos 45° y=y’
M=t
PE=KE
The E=1/sqrt2 implies the two-pole solution. The two poles are KE and PE or Mass to time.
Keywords:
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